假设我们有一个整型变量，其大小为 4 字节，还有另一个指针变量，其大小为 8 字节。那么下面的输出会是什么？
示例
#includeusing namespace std; main() { int a[4][5][6]; int x = 0; int* a1 = &x; int** a2 = &a1; int*** a3 = &a2; cout << sizeof(a) << " " << sizeof(a1) << " " << sizeof(a2) << " " << sizeof(a3) << endl; cout << (char*)(&a1 + 1) - (char*)&a1 << " "; cout << (char*)(&a2 + 1) - (char*)&a2 << " "; cout << (char*)(&a3 + 1) - (char*)&a3 << " "; cout << (char*)(&a + 1) - (char*)&a << endl; cout << (char*)(a1 + 1) - (char*)a1 << " "; cout << (char*)(a2 + 1) - (char*)a2 << " "; cout << (char*)(a3 + 1) - (char*)a3 << " "; cout << (char*)(a + 1) - (char*)a << endl; cout << (char*)(&a[0][0][0] + 1) - (char*)&a[0][0][0] << " "; cout << (char*)(&a[0][0] + 1) - (char*)&a[0][0] << " "; cout << (char*)(&a[0] + 1) - (char*)&a[0] << " "; cout << (char*)(&a + 1) - (char*)&a << endl; cout << (a[0][0][0] + 1) - a[0][0][0] << " "; cout << (char*)(a[0][0] + 1) - (char*)a[0][0] << " "; cout << (char*)(a[0] + 1) - (char*)a[0] << " "; cout << (char*)(a + 1) - (char*)a; }
解决这个问题，我们可以遵循以下一些重要点：
整数大小为4字节（32位），指针大小为8字节。如果我们将1与指针相加，它将指向下一个立即类型。
-
&a1的类型是int **，&a2是int ***，&a3的类型是int ****。这里都指向指针。如果我们加1，我们将添加8字节。
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a [0] [0] [0]是一个整数，&a [0] [0] [0]是int *，a [0] [0]是int *，&a [0] [0]的类型是int（*）[6]，依此类推。所以&a的类型是int（*）[4] [5] [6]。
输出
480 8 8 8 8 8 8 480 4 8 8 120 4 24 120 480 1 4 24 120
