使用pthread在C/C++中实现矩阵的加法和减法

这里我们将看到如何使用多线程环境执行矩阵加法和减法。 pthread用于在C或C++中同时执行多个线程。

有两个矩阵A和B。每个矩阵的阶数为(m x n)。每个线程将获取每一行，并执行加法或减法。因此，对于 m 行，有 m 个不同的线程。

OpenCV

开源计算机视觉库拥有超过2500个算法，提供详细的文档和实时计算机视觉的示例代码。它可以在Windows、Linux、Mac OS X、Android、iOS上运行，并通过JavaScript在您的浏览器中使用。语言：C++、Python、Julia、Javascript主页：https://opencv.org问答论坛：https://forum.opencv.org/文档：https://docs.opencv.org源代码：https://github.com/opencv请特别关注我们的教程！ht

下载

示例

#include
#include 
#include 
#include 
#define CORE 3
#define MAX 3
using namespace std;
int AMat[MAX][MAX] = {{10, 20, 30},
   {40, 50, 60},
   {70, 80, 50}
};
int BMat[MAX][MAX] = {{80, 60, 20},
   {30, 20, 15},
   {10, 14, 35}
};
pthread_t thread[CORE * 2];
int add[MAX][MAX], sub[MAX][MAX];
void* addMatrices(void* arg) {
   intptr_t core = (intptr_t)arg;
   // Each thread computes 1/3rd of matrix addition
   for (int i = core * MAX / 3; i < (core + 1) * MAX / 3; i++) {
      for (int j = 0; j < MAX; j++) {
         add[i][j] = AMat[i][j] + BMat[i][j];
      }
   }
}
void* subtraction(void* arg) {
   intptr_t core = (intptr_t)arg;
   // Each thread computes 1/3rd of matrix subtraction
   for (int i = core * MAX / 3; i < (core + 1) * MAX / 3; i++) {
      for (int j = 0; j < MAX; j++) {
         sub[i][j] = AMat[i][j] - BMat[i][j];
      }
   }
}
void display(){
   cout << "Matrix A: " << endl;
   for(int i = 0; i < MAX; i++) {
      for(int j = 0; j < MAX; j++) {
         cout << AMat[i][j] << " ";
      }
      cout << endl;
   }
   cout << "\nMatrix B: " << endl;
   for(int i = 0; i < MAX; i++) {
      for(int j = 0; j < MAX; j++) {
         cout << BMat[i][j] << " ";
      }
      cout << endl;
   }
}
void displayRes(){
   cout << "\nAddition: " << endl;
   for(int i = 0; i < MAX; i++) {
      for(int j = 0; j < MAX; j++) {
         cout << add[i][j] << " ";
      }
      cout << endl;
   }
   cout << "\nSubtraction: " << endl;
   for(int i = 0; i < MAX; i++) {
      for(int j = 0; j < MAX; j++) {
         cout << sub[i][j] << " ";
      }
      cout << endl;
   }
}
main() {
   display();
   int step = 0;
   for (int i = 0; i < CORE; i++) {
      pthread_create(&thread[i], NULL, &addMatrices, (void*)step);
      pthread_create(&thread[i + CORE], NULL, &subtraction, (void*)step);
      step++;
   }
   for (int i = 0; i < CORE * 2; i++) {
      pthread_join(thread[i], NULL);
   }
   displayRes();
}

输出

Matrix A:
10 20 30
40 50 60
70 80 50
Matrix B:
80 60 20
30 20 15
10 14 35
Addition:
90 80 50
70 70 75
80 94 85
Subtraction:
-70 -40 10
10 30 45
60 66 15