适配ios9出现的问题：-canOpenURL: failed for URL-PHP中文网问答

-canOpenURL: failed for URL: "wtloginmqq2://qzapp" - error: "(null)"
2015-09-13 15:51:10.903[2948:1118021] -canOpenURL: failed for URL: "mqqopensdkapiV3://qzapp" - error: "(null)"
2015-09-13 15:51:10.904[2948:1118021] -canOpenURL: failed for URL: "mqqwpa://qzapp" - error: "(null)"
2015-09-13 15:51:10.905[2948:1118021] -canOpenURL: failed for URL: "mqqopensdkapiV2://qzapp" - error: "This app is not allowed to query for scheme mqqopensdkapiV2"
2015-09-13 15:51:10.906[2948:1118021] -canOpenURL: failed for URL: "mqqOpensdkSSoLogin://qqapp" - error: "This app is not allowed to query for scheme mqqOpensdkSSoLogin"
2015-09-13 15:51:10.906[2948:1118021] -canOpenURL: failed for URL: "mqq://qqapp" - error: "This app is not allowed to query for scheme mqq"
2015-09-13 15:51:10.907[2948:1118021] -canOpenURL: failed for URL: "mqzoneopensdkapiV2://qzapp" - error: "This app is not allowed to query for scheme mqzoneopensdkapiV2"
2015-09-13 15:51:10.908[2948:1118021] -canOpenURL: failed for URL: "mqzoneopensdkapi19://qzapp" - error: "This app is not allowed to query for scheme mqzoneopensdkapi19"
2015-09-13 15:51:10.909[2948:1118021] -canOpenURL: failed for URL: "mqzoneopensdkapi://qzapp" - error: "This app is not allowed to query for scheme mqzoneopensdkapi"
2015-09-13 15:51:10.910[2948:1118021] -canOpenURL: failed for URL: "mqzoneopensdk://qzapp" - error: "This app is not allowed to query for scheme mqzoneopensdk"
2015-09-13 15:51:10.911[2948:1118021] -canOpenURL: failed for URL: "mqzone://qzapp" - error: "This app is not allowed to query for scheme mqzone"
2015-09-13 15:51:10.911[2948:1118021] -canOpenURL: failed for URL: "wtloginmqq2://qzapp" - error: "(null)"
2015-09-13 15:51:10.912[2948:1118021] -canOpenURL: failed for URL: "mqqopensdkapiV3://qzapp" - error: "(null)"

现在app在ios9运行出现了这些，查了下资料。
根据网上的做法。

iOS9 URL Schemes 

除了要在项目info URL Types中设置URL Schemes，还需要在info.plist里面增加可信任的调用app，否则回报如下错误

-canOpenURL: failed for URL: "weixin://app/wx9c8771d3c07dfd30/" - error: "This app is not allowed to query for scheme weixin"

-canOpenURL: failed for URL: "wtloginmqq2://qzapp" - error: "This app is not allowed to query for scheme wtloginmqq2"

info.plist加入

LSApplicationQueriesSchemes



urlscheme

urlscheme2

urlscheme3

urlscheme4

我加入之后。

本来加入之前提示：
-canOpenURL: failed for URL: "mqqopensdkapiV2://qzapp" - error: "This app is not allowed to query for scheme mqqopensdkapiV2"

加入之后，error原因就没有了。如下：

-canOpenURL: failed for URL: "mqqopensdkapiV2://qzapp" - error: "(null)"

可是仍然是fail的。不知道如何解决？

<key>LSApplicationQueriesSchemes</key> <array> <string>mqqOpensdkSSoLogin</string> <string>mqzone</string> <string>sinaweibo</string> <string>alipayauth</string> <string>alipay</string> <string>safepay</string> <string>mqq</string> <string>mqqapi</string> <string>mqqopensdkapiV3</string> <string>mqqopensdkapiV2</string> <string>mqqapiwallet</string> <string>mqqwpa</string> <string>mqqbrowser</string> <string>wtloginmqq2</string> <string>weixin</string> <string>wechat</string> </array>加了15条才实现

全部回复(11)

大家讲道理2017-04-17 16:43:05 11楼

要使用iOS9的真机！不要用模拟器测试，不然一直报-canOpenURL: failed for URL: "XXXXXXXXXX" - error: "(null)"。我真机测试通过了。

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高洛峰2017-04-17 16:43:05 10楼

qq登录绑定，qq支付，qq分享
微信支付，微信登录绑定
新浪登录绑定
支付宝支付，支付宝登录绑定

迷茫2017-04-17 16:43:05 9楼

找到答案了吗？我加上了也还是报错null

巴扎黑2017-04-17 16:43:05 8楼

添加了还是会继续报错吗？那个url scheme的

迷茫2017-04-17 16:43:05 7楼

添加了依然会继续报错那个url scheme的有谁看看怎么解决的啊

PHP中文网2017-04-17 16:43:05 6楼

这个模拟器的一个 bug，如果使用iOS9的真机就可以避免出现该问题，估计 Xcode 后续的升级中会修复掉。

测试 URL Scheme 尽量避免使用模拟器测试，不然一直报

-canOpenURL: failed for URL: "XXXXXXXXXX" - error: "(null)"。

亲测真机通过。

更多 iOS9适配问题请访问--》《iOS9适配系列教程》

伊谢尔伦2017-04-17 16:43:05 5楼

-canOpenURL: failed for URL: "mqzone://sdk" - error: "(null)" 在真机上，仍然会报这个，已经添加<string>mqzone</string>了。而且重启app就好了，一旦调用TecentOAuth的

(void)logout:(id<TencentSessionDelegate>)delegate;
这个方法，再执行登录授权，就会报刚刚那个错误。

我现在把这句删掉了，退出登录的时候直接清除一下TecentOAuth的accessToken，就没问题了

巴扎黑2017-04-17 16:43:05 4楼

如果你的应用使用了如SSO授权登录或跳转分享功能，在iOS9下就需要增加一个可跳转的白名单，指定对应跳转App的URL Scheme，否则将在第三方平台判断是否跳转时用到的canOpenURL时返回NO，进而只进行webview授权或授权/分享失败。

PHP中文网2017-04-17 16:43:05 3楼

-canOpenURL: failed for URL: "weixin://app/wxa25a198a4530b133/" - error: "(null)"
scheme 都添加了而且是真机
大神求指导

伊谢尔伦2017-04-17 16:43:05 2楼

这个解决2个问题就可以了：1首先在info.plist文件里添加

<key>LSApplicationQueriesSchemes</key>

<array>
    <string>hui123BBB</string>
    <!--        <string>urlscheme2</string>-->
    <!--        <string>urlscheme3</string>-->
    <!--        <string>urlscheme4</string>-->
</array>

2、然后，urlscheme 填对就可以了：
UIApplication *app = [UIApplication sharedApplication];

NSURL *url = [NSURL URLWithString:@"hui123BBB://"];

[[UIApplication sharedApplication] openURL:url];

if ([app canOpenURL:url]) {

    [app openURL:url];
    
}else{
    NSLog(@"打开错误");
}