我如下代码发送请求,为什么在服务其上。用request.getParamter("name")
那不到值呢?
TTURLRequest *request = [self request:url Delegate:delegate]; [request setHttpMethod:@"POST"]; [request.parameters setObject:@"agassi_yzh" forKey:@"name"]; [request send];
Copyright 2014-2026 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号
认证高级PHP讲师