given a number n and we have to print the arrow star pattern of maximum n number of stars.
The star pattern of input 4 will look like −
Example
Input: 3 Output:
Input: 5 Output:
下面使用的方法如下：
- 以整数形式输入。
- 然后打印n个空格和n个星号。
- 递减直到n>1。
- 现在递增直到n。
- 并按照递增顺序打印空格和星号。
算法
Start
In function int arrow(int num)
Step 1-> declare and initialize i, j
Step 2-> Loop For i = 1 and i <= num and i++
Loop For j = i and j < num and j++
Print a space
Loop For j = i and j <= num and j++
Print "*"
Print newline
Step 3-> Loop For i = 2 and i <= num and i++
Loop For j= 1 and j < I and j++
Print a space
Loop For j = 1 and j <= i and j++
Print "*"
Print newline
In function int main()
Step 1-> declare and initialize num = 4
Step 2-> call arrow(num)Example
演示
#include <stdio.h>
// arrow function
int arrow(int num) {
int i, j;
// Prints the upper part of the arrow
for (i = 1; i <= num; i++) {
// to print the spaces
for (j = i; j < num; j++) {
printf(" ");
}
// to print the * for the pattern
for (j = i; j <= num; j++) {
printf("*");
}
printf("</p><p>");
}
// Prints lower part of the arrow
for (i = 2; i <= num; i++) {
// to print the spaces
for (j = 1; j < i; j++) {
printf(" ");
}
// to print the * for the pattern
for (j = 1; j <= i; j++) {
printf("*");
}
printf("</p><p>");
}
return 0;
}
int main() {
// get the value from user
int num = 4;
// function calling
arrow(num);
return 0;
}输出
如果运行上述代码，将生成以下输出 −
