当时碰到的几个技术问题是：
1.从web传递相关的参数给application,
解决办法：用动态jnlp文件（jsp实现jnlp）,同时用到如下传参办法
application-desc Element
the application element indicates that the jnlp file is launching an application (as opposed to an applet). the application element has an optional attribute, main-class, which can be used to specify the name of the application's main class, i.e., the class that contains the public static void main(string argv[]) method where execution must begin.
The
main-classattribute can be omitted if the first JAR file specified in the JNLP file contains a manifest file containing themainclass.Arguments can be specified to the application by including one or more nested argument elements. For example:
application-desc main-class="Main">
argument>arg1argument>
argument>arg2argument>
application-desc>
2.如何将application处理的结果传回给web server
解决办法，用URLConnection结合从jnlp中传来的web url (为一个后台处理的servlet地址),sessionID（用于识别当前用户，权限等判断）去创建一个新的url对象，并通过它在application和web server之间传递数据。在后台的servlet中通过sessionid,从session listener中找到当前用户，
private String getStringPostRequest(String command) throws Exception {
DataOutputStream dos=null;
ObjectInputStream dis=null;
try {
URLConnection urlConn = new URL(webServerStr).openConnection();
urlConn.setDoOutput(true);
urlConn.setDoInput(true);
urlConn.setAllowUserInteraction(false);
urlConn.setUseCaches(false);
urlConn.setRequestProperty(
"Content-Type",
"application/x-www-form-urlencoded");
dos = new DataOutputStream(urlConn.getOutputStream());
dos.writeBytes(command + "&sessionId=" + this.sessionId);
dos.close();
// read input from servlet
dis =
new ObjectInputStream(urlConn.getInputStream());
String ret = dis.readObject().toString();
dis.close();
return ret;
} catch (Exception e) {
throw e;
} finally{
if ( dos!=null) dos.close();
if ( dis!=null) dis.close();
}
}
后台sevlet:
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException
{
HttpSession hSession = request.getSession();
System.out.println("Application:" + hSession.getId());
if(MyListener.getSessionById(request.getParameter("sessionId")) != null)
hSession = MyListener.getSessionById(request.getParameter("sessionId"));
System.out.println("OK" + hSession);
..............}
sessionlistener:
import java.util.HashMap;
import java.util.Map;
import javax.servlet.ServletContextEvent;
import javax.servlet.ServletContextListener;
import javax.servlet.http.*;
public class SessionsListener
implements ServletContextListener, HttpSessionListener
{
在整本书中我们所涉及许多的Flex框架源码，但为了简洁，我们不总是显示所指的代码。当你阅读这本书时，要求你打开Flex Builder，或能够访问Flex3框架的源码，跟随着我们所讨论源码是怎么工作及为什么这样做。 如果你跟着阅读源码，请注意，我们经常跳过功能或者具体的代码，以便我们可以对应当前的主题。这样能防止我们远离当前的主题，主要是讲解代码的微妙之处。这并不是说那些代码的作用不重要，而是那些代码处理特别的案例，防止潜在的错误或在生命周期的后面来处理，只是我们当前没有讨论它。有需要的朋友可以下载看看
static Map map = new HashMap();
public SessionsListener()
{
}
public void contextInitialized(ServletContextEvent servletcontextevent)
{
}
public void contextDestroyed(ServletContextEvent servletcontextevent)
{
}
public void sessionCreated(HttpSessionEvent httpsessionevent)
{
HttpSession httpsession = httpsessionevent.getSession();
map.put(httpsession.getId(), httpsession);
}
public void sessionDestroyed(HttpSessionEvent httpsessionevent)
{
HttpSession httpsession = httpsessionevent.getSession();
map.remove(httpsession.getId());
}
public static HttpSession getSessionById(String s)
{
return (HttpSession)map.get(s);
}
}
3.jar包数字签名问题
4.java webstart cache问题即:JNLP file caching
http://forum.java.sun.com/thread.jspa?forumID=38&threadID=556847
(1)
If you remove the href= parameter from the jnlp tag, Java Web Start 1.4.2 will not cache the jnlp file.
1.5.0 still will, but if you also remove the
(2)
It seems the issue is with generated JNLP files.
Try the following:
response.addDateHeader("Date", Calendar.getInstance().getTime().getTime());
response.addDateHeader("Last-Modified", Calendar.getInstance().getTime().getTime());
Seems to have solved the problem for us.
