PHP5中使用DOM控制XML实现代码_php技巧

/************************************************
** use XML in PHP5
** reference site:
** http://cn.php.net/manual/zh/ref.dom.php
** the follow codes need PHP5 support
*************************************************/

//首先要创建一个DOMDocument对象
$dom = new DomDocument();
//然后载入XML文件
$dom -> load("test.xml");

//输出XML文件
//header("Content-type: text/xml;charset=gb2312");
//echo $dom -> saveXML();

//保存XML文件，返回值为int（文件大小，以字节为单位）
//$dom -> save("newfile.xml");

echo "

---

取得所有的title元素:

---

";
$titles = $dom -> getElementsByTagName("title");
foreach ($titles as $node){
echo $node -> textContent . "
";
//这样也可以
//echo $node->firstChild->data . "
";
}

/*
echo "

---

从根结点遍历所有结点：
";
foreach ($dom->documentElement->childNodes as $items) {
//如果节点是一个元素(nodeType == 1)并且名字是item就继续循环
if ($items->nodeType == 1 && $items->nodeName == "item") {
foreach ($items->childNodes as $titles) {
//如果节点是一个元素，并且名字是title就打印它.
if ($titles->nodeType == 1 && $titles->nodeName == "title") {
print $titles->textContent . "\n";
}
}
}
}
*/

//使用XPath查询数据
echo "

---

使用XPath查询的title节点结果:

---

";
$xpath = new domxpath($dom);
$titles = $xpath->query("/rss/channel/item/title");
foreach ($titles as $node){
echo $node->textContent."
";
}
/*
这样和使用getElementsByTagName()方法差不多，但是Xpath要强大的多
深入一点可能是这样：
/rss/channel/item[position() = 1]/title 返回第一个item元素的所有
/rss/channel/item/title[@id = '23'] 返回所有含有id属性并且值为23的title
/rss/channel/&folder&/title 返回所有articles元素下面的title(译者注：&folder&代表目录深度)
*/


//向DOM中写入新数据
$item = $dom->createElement("item");
$title = $dom->createElement("title");
$titleText = $dom->createTextNode("title text");
$title->appendChild($titleText);
$item->appendChild($title);
$dom->documentElement->getElementsByTagName('channel')->item(0)->appendChild($item);

//从DOM中删除节点
//$dom->documentElement->RemoveChild($dom->documentElement->getElementsByTagName("channel")->item(0));
//或者使用xpath查询出节点再删除
//$dom->documentElement->RemoveChild($xpath->query("/rss/channel")->item(0));
//$dom->save("newfile.xml");

//从DOM中修改节点数据
//修改第一个title的文件
//这个地方比较笨，新创建一个节点，然后替换旧的节点。如果哪位朋友有其他好的方法请一定要告诉我
$firstTitle = $xpath->query("/rss/channel/item/title")->item(0);
$newTitle = $dom->createElement("title");
$newTitle->appendChild(new DOMText("This's the new title text!!!"));
$firstTitle->parentNode->replaceChild($newTitle, $firstTitle);
//修改属性
//$firstTitle = $xpath->query("/rss/channel/item/title")->item(0);
//$firstTitle->setAttribute("orderby", "4");
$dom->save("newfile.xml");

echo "

---

查看newfile.xml";

//下面的代码获得并解析php.net的首页，将返第一个title元素的内容。
/*
$dom->loadHTMLFile("http://www.php.net/");
$title = $dom->getElementsByTagName("title");
print $title->item(0)->textContent;
*/
?>

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