php判断来访蜘蛛信息的函数

php判断来访蜘蛛的信息的函数，具体代码如下：

<p>function get_naps_bot(){</p><div class="aritcle_card flexRow">
                                                        <div class="artcardd flexRow">
                                                                <a class="aritcle_card_img" href="/ai/2507" title="百度AI搜"><img
                                                                                src="https://img.php.cn/upload/ai_manual/001/246/273/176907409582411.png" alt="百度AI搜"  onerror="this.onerror='';this.src='/static/lhimages/moren/morentu.png'" ></a>
                                                                <div class="aritcle_card_info flexColumn">
                                                                        <a href="/ai/2507" title="百度AI搜">百度AI搜</a>
                                                                        <p>百度全新AI搜索引擎</p>
                                                                </div>
                                                                <a href="/ai/2507" title="百度AI搜" class="aritcle_card_btn flexRow flexcenter"><b></b><span>下载</span> </a>
                                                        </div>
                                                </div>	$useragent=strtolower($_SERVER['HTTP_USER_AGENT']);<br />	if(strpos($useragent,'googlebot')!==false){<br />		return 'Googlebot';<br />	}<br />	if(strpos($useragent,'msnbot')!==false){<br />		return 'MSNbot';<br />	}<br />	if(strpos($useragent,'slurp')!==false){<br />		return 'Yahoobot';<br />	}<br />	if(strpos($useragent,'baiduspider')!==false){<br />		return 'Baiduspider';<br />	}<br />	if(strpos($useragent,'sohu-search')!==false){<br />		return 'Sohubot';<br />	}<br />	if(strpos($useragent,'lycos')!==false){<br />		return 'Lycos';<br />	}<br />	<br />	if(strpos($useragent,'robozilla')!==false){<br />		return 'Robozilla';<br />	}<br />	return false;<br />}