测试React中的上一个和下一个按钮功能失败-PHP中文网问答

我的React代码测试失败：如果我写错了，你能帮忙写对吗？我尝试使用screen.getByRole('button', {name: '>'})来获取下一个按钮，使用screen.getByRole('button', {name: '<'})来获取上一个按钮，甚至尝试了下面提到的测试代码，但测试一直失败。

export default function App() {

  return (
    <div className="App">
      <div>
        {dogs
          .map((value, key) => (
            <div className="card-container" key={key}>
              <div>
                <img className="img" src={value.imgUrl} alt={value.title} />
              </div>
              <div className="card-footer">
                {dogCurrPage !== 1 ? (
                  <button className="back-button" onClick={() => previous()}>
                    {"<"}
                  </button>
                ) : null}
                <span className="card-title-text">{value.title}</span>
                {dogCurrPage !== dogs.length - 1 ? (
                  <button className="next-button" onClick={() => next()}>
                    {">"}
                  </button>
                ) : null}{" "}
              </div>
            </div>
          ))}
      </div>
    </div>
  );
}

describe("App", () => {
  it("正确处理上一个按钮的点击", () => {
    render(<App />);

    fireEvent.click(screen.getByText("<"));
  });

  it("正确处理下一个按钮的点击", () => {
    render(<App />);

    fireEvent.click(screen.getByText(">"));
  });
});

describe("App", () => { it("正确渲染应用程序", async() => { render( < App / > ); // 根据您的UI组件添加更具体的断言 expect(screen.getByText("Fetch Api, display 1 card, add comments and likes to those comments")).toBeInTheDocument(); }); it("正确处理上一个按钮的点击", async() => { render( < App / > ); fireEvent.click(screen.getByRole("button", { name: "<" })); // 添加断言以检查点击上一个按钮后的行为 }); it("正确处理下一个按钮的点击", async() => { render( < App / > ); fireEvent.click(screen.getByRole("button", { name: ">" })); // 添加断言以检查点击下一个按钮后的行为 }); });