我已经编写了一个用于读取CSV文件并根据时间和日期在网站上发布结果的广播节目表的PHP脚本。然而,它似乎会发布两次。
以下是脚本内容:
<?php
// Step 1: Replace 'data.csv' with the path to your CSV file
$csvFile = 'schedule.csv';
// Step 2: Read CSV and store its contents in an array
if (($handle = fopen($csvFile, 'r')) !== false) {
$csvData = [];
while (($data = fgetcsv($handle)) !== false) {
$csvData[] = $data;
}
fclose($handle);
} else {
die("Error opening CSV file.");
}
// Step 3: Get the current day and time
$currentDay = date('l'); // l gives the full textual representation of the day (e.g., "Monday")
$currentHour = date('H'); // H gives the hour in 24-hour format (e.g., "13" for 1 PM)
// Adjust hour offset below.
$Hour = $currentHour+1;
// Step 4: Filter the array based on the current day and time
$filteredData = [];
foreach ($csvData as $row) {
// Assuming that your CSV file has a "Day" column and a "Time" column
$day = $row[0];
$time = intval($row[1]);
$program_name= $row[2];
$program_when= $row[2];
$program_img= $row[4];
// Check if the row matches the current day and time
if ($day === $currentDay && $Hour >= $time) {
$filteredData[] = $row;
}
}
// Step 5: Display the filtered data with CSS classes for each row
if (count($filteredData) > 0) {
foreach ($filteredData as $row) {
echo "<div class='row'>";
echo "<div class='col-5'>";
echo "<img src='$row[4]' width='90' height='90' border='0'>";
echo "</div>";
echo "<div class='col-7'>";
echo "<h3>$row[2]<br>$row[3]</h3>";
echo "</div>";
echo "</div>";
}
} else {
echo 'Not available.';
}
这是我在CSV文件中进行测试的数据:
Friday,12,MMV,until 1pm,top_mmv.png Friday,13,MMV,until 2pm,top_mmv.png Friday,14,MMV,until 3pm,top_mmv.png Friday,15,MMV,until 4pm,top_mmv.png
但是当到达周五下午2点时,它会同时发布1点和2点的行。请问我做错了什么?
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你需要指定收集数据的条件,
if ($day === $currentDay && $Hour >= $time) {例如,现在的当前时间是14点(加1小时是你的调整)。
$Hour >= $time
我认为你可以看到问题出在哪里。